nilai dari ²log 6 - ²log 4 + 1/2 ²log 16 - ²log 48

Kelas 10 Matematika
Bab Logaritma

²log 6 - ²log 4 + (1/2) . ²log 16 - ²log 48
= ²log 6 - ²log 48 - ²log 4 + (1/2) . ²log 16
= ²log (6/48) - ²log 2² + (1/2) . ²log 2⁴
= ²log (1/8) - 2 + (1/2) . 4
= ²log 2⁻³ - 2 + 2
= -3 

²log6-²log4+½²log16-²log48
=²log(2×3)-²log2²+½²log2⁴-²log(2⁴×3)
=²log2+²log3-2²log2+½.4²log2-(²log2⁴+²log3)
=1+²log3-2+2-(4+²log3)
=-3...

#gunakan sifat-sifat logaritma
#smoga membantush_!