Matematika

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[tex] \frac{ \sqrt{3} + 2}{ \sqrt{3 - 2} } = [/tex]
tolongin donkk

2 Jawaban

  • [tex] \frac{ \sqrt{3} + 2 }{ \sqrt{3} - 2} = \frac{( \sqrt{3} + 2)( \sqrt{3} + 2)}{ (\sqrt{3} - 2)( \sqrt{3} + 2)} \\ = \frac{3 + 4 \sqrt{3} + 4}{3 - 4} \\ = \frac{7 + 4 \sqrt{3} }{ - 1} \\ = - 7 - 4 \sqrt{3} [/tex]
  • smoga membantush_!

    yuhuuu :)
    Gambar lampiran jawaban shintanurkaafi

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