ni kak tolong bantu ya

(2x-3)(x-3)/4x-9=2x-3/2x-3=1

[tex] \frac{2x^{2} - 3x - 9}{4 {x}^{2} - 9 } \\ = \frac{(2x + 3)(x - 3)}{(2x + 3)(2x - 3)} \\ = \frac{x - 3}{2x - 3} [/tex]