nilai dari (√28-√12)(2√7+2√3) =

[tex]( \sqrt{28} - \sqrt{12} )(2 \sqrt{7} + 2 \sqrt{3} ) \\ = 2 \sqrt{196} - 2 \sqrt{84} + 2 \sqrt{84} - 2 \sqrt{36} \\ = 2 \sqrt{196} - 2 \sqrt{36} \\ = 2 \times 14 - 2 \times 6 \\ = 28 - 12 \\ = 16[/tex]