persamaan garis h adalah

gradien =y/x
m= [tex] \frac{6}{-4} [/tex] = [tex] \frac{3}{-2} [/tex]
gradien garis h = -1 
m h = [tex] \frac{2}{3} [/tex]

masukkan ke persamaan
y-y1 = m ( x-x1)
y-1=[tex] \frac{2}{3} [/tex] ( x-0)
3y-3=2x
3y-2x=3

jawbannya b
 

pers. garis yg melalui titik (-4,0) dan (0,6)
[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \frac{y - 0}{6 - 0} = \frac{x + 4}{0 + 4} \\ \frac{y}{6} = \frac{x + 4}{ 4} \\ 4y = 6(x + 4) \\ 4y = 6x + 24[/tex]
m1 = 6/4 = 3/2

Garis h melalui titik (0,1) dan tegak lurus terhadap garis tersebut.
Jadi,
m1 × m2 = -1
3/2 × m2 = -1
m2 = -1 : 3/2
m2 = -1 × 2/3
m2 = -2/3

y-y1 = m (x-x1)
y-1 = -2/3 (x - 0)
y-1 = -2/3x
y + 2/3x = 1
3y + 2x = 3

Jawaban A.