R1 = 5 . R2 = 10 . R3 = 3 . R4 = 6 . R5 = 15 . W itung secara paralel yg R1.R2.R3.R4 Hasil 1.25 trus langsung dijumlah R5 = 15. Jadi 1.25+15=16.25? jadi Rtotal
Fisika
saepulabdula
Pertanyaan
R1 = 5 . R2 = 10 . R3 = 3 . R4 = 6 . R5 = 15 .
W itung secara paralel yg R1.R2.R3.R4 Hasil 1.25 trus langsung dijumlah R5 = 15. Jadi 1.25+15=16.25? jadi Rtotal = 16.25 ?
W itung secara paralel yg R1.R2.R3.R4 Hasil 1.25 trus langsung dijumlah R5 = 15. Jadi 1.25+15=16.25? jadi Rtotal = 16.25 ?
2 Jawaban
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1. Jawaban tauhidynwa
Rparalel=1/R1+1/R2+1/R3+1/R4
=1/5+1/10+1/3+1/6
=6+3+10+5/30
=24/30
dibalik 30/24=1,25
Rtot=Rparalel+R5
=1,25+15
=16,25 ohm -
2. Jawaban iday
*) seri 1: Rs1 = R1 + R2 = 5 + 10 = 15 ohm
**) seri 2: Rs2 = R3 + R4 = 3 + 6 = 9 ohm
***) paralel : 1/Rp = 1/Rs1 + 1/Rs2 = 1/15 + 1/9 = (3 + 5)/45 = 8/45
Rp = 45/8 = 5,625 ohm
****) seri : Rs = Rp + R5 = 5,625 +15 = 20,625 ohm
jadi, R total = 20,625 ohm