hitunglah nilai integral 0 sampai 2 3(x+1)(x-6)dx

[tex] \int\limits^2_0 {3(x+1)(x-6)} \, dx = 3\int\limits^2_0 {x^2-5x-6} \, dx [/tex]
[tex]| {\frac{1}{3}x^3-\frac{5}{2}x^2-6x} |_0^2 =-\frac{58}{3}[/tex]