tentukan besar sudut terkecil yang terbentuk oleh kedua jarum jam pada waktu berikut:02:30,09:30,01:20,11:35,02:25,16:45 beserta caranya yah :) poin hadiah:80

Mapel : Matematika
Materi : Aritmatika
Sub Materi : Besar Sudut Jarum Jam
————————————————————
02.30 ⬇️⬇️⬇️
= Jarum Panjang - Jarum Pendek
= (30 × 6)° - ((2 × 30)° + (30/60 × 30))°
= 180° - (60 + 15)°
= 180° - 75°
= 105° ✔️

09.30 ⬇️⬇️⬇️
= Jarum Panjang - Jarum Pendek
= (30 × 6)° - ((36/18 × 30)°+ (30/60 × 30))°
= 180° - (60 + 15)°
= 180° - 75°
= 105° ✔️

01.20 ⬇️⬇️⬇️
= Jarum Panjang - Jarum Pendek
= (20 × 6)° - ((1 × 30)° + (20/60 × 30))°
= 120° - (30 + 10)°
= 120° - 40°
= 80° ✔️

11.35 ⬇️⬇️⬇️
= (-35 × 6)° + ((11 × 30)°+(35/60 × 30))°
= - 210° + (330 + 17,5)°
= - 210 + 347,5°
= 137,5° ✔️

02.25 ⬇️⬇️⬇️
= (25 × 6)° - ((2 × 30)° + (25/60 × 30))°
= 150° - (60 + 12,5)°
= 150° - 72,5°
= 77,5° ✔️

16.45 = 04.45 ⬇️⬇️⬇️
= Jarum Panjang - Jarum Pendek
= (45 × 6)° - ((4 ×30)° + (45/60 × 30))°
= 270° - (120 + 22,5)°
= 270° - 142,5°
= 127,5° ✔️

Semoga bermanfaat.....
-Prisco