Matematika

Pertanyaan

Diketahui sin α = 4/5 , cos β = 7/25 , α dan β sudut lancip. Nilai cos ( α - β ) =.....??

2 Jawaban

  • sin a = 4/5
    cos a = 3/5

    cos b = 7/25
    sin b = 24/25

    cos (a-b) = sin a × sin b + cos a × cos b
    cos (a-b) = 4/5 × 24/25 + 3/5 × 7/25
    cos (a-b) = 96/125 + 21/125 = 117/125
  • sin a = depan/miring
    = 4/5

    cos a = samping/miring
    samping = √(5²-4²)
    = √(25-16)
    = √9
    = 3
    cos a = 3/5

    sin b = depan/miring
    = 7/25

    cos b = samping/miring
    samping = √(25²-7²)
    = √(625/49)
    = √576
    = 24
    cos b = 24/25

    cos (a -b) = cos a cos b + sin a sin b
    = (3/5)(24/25) + (4/5)(7/25)
    = (72/125) +(28/125)
    = 100/125
    = 4/5

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