Matematika

Pertanyaan

bentuk sederhana dari 22per 1+2akar3

2 Jawaban

  • Mapel : Matematika
    Materi : Pecahan
    Sub Materi : Penyederhanaan
    ————————————————————
    [tex] \frac{22}{1 + 2 \sqrt{3} } \\ = \frac{22}{1 + 2 \sqrt{3} } \times \frac{1 - 2 \sqrt{3} }{1 - 2 \sqrt{3} } \\ = \frac{22(1 - 2 \sqrt{3} )}{1 - 4.3} \\ = \frac{22(1 - 2 \sqrt{3}) }{1 - 12} \\ = \frac{22(1 - 2 \sqrt{3} )}{ - 11} \\ = - 2(1 - 2 \sqrt{3} ) \\
    = - 2 + 4 \sqrt{3} \\
    = 4 \sqrt{3} - 2[/tex]

    Semoga bermanfaat.....
    -Prisco
  • 22/(1 + 2V3)

    = 22/(1 + 2V3) × (1 - 2V3)/(1 - 2V3)

    = 22(1 - 2V3)/(1 - 2V3)(1 + 2V3)

    = (22 - 44V3)/(1 - 12)

    = (22 - 44V3)/(-11)

    = -2 + 4V3

    = 4V3 - 2

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