tentukan persamaan garis melalui titik (12 , -18 ) dan tegak lurus garis 3x +y = 10

mg2=-a/b=-3/1

g1 tegak lurus g2=m1.m2=-1
m1.(-3/1)=-1
m1=-1: (-3/1)
=-1x(-1/3)
=1/3

y1-y2=m(x-x1)
y-(-18)=1/3 (x-12)
y=1/3x - 12/3 - 18
y=1/3x - 12/3 - 54/3
y=1/3x - 66/3 (x3)
3y= x-66
x-3y-66=0

sorry kalau salah