tolong jawab No 7 dan 8 ya :)

nomer 7
[tex] {9}^{x + 1} = 27 \\ {3}^{2( \times + 1)} = {3}^{3} \\ 2(x + 1) = 3 \\ 2x + 2 = 3 \\ 2x = 3 - 2 \\ 2x = 1 \\ x = \frac{1}{2} [/tex]
(D)

nomer 8

[tex] \sqrt{2x - 1} = 3 \\ {( \sqrt{2x - 1} )}^{2} = {3}^{2} \\ 2x - 1 = 9 \\ 2x = 9 + 1 \\ 2x = 10 \\ x = \frac{10}{2} = 5[/tex]
(B)

semoga membantu ^^