Persamaan garis yang melalui titik ( -4 , 2) dan tegak lurus dengan 2×+6y-12=0

(-4,2) tgk lurs 2x+6y-12=0
6x-2y=
6×-4-2×2=
-24-4
-20
6x-2y=-20

[tex]2x + 6y - 12 = 0 \\ m = \frac{ - a}{b} = \frac{ - 2}{6} = - \frac{1}{3} \\ \\ m \times m1 = - 1 \\ - \frac{1}{3} \times m1 = - 1 \\ m1 = - 1 \div (- \frac{1}{3} ) \\ m1 = - 1 \times ( - \frac{3}{1} ) \\ m1 = 3 \\ \\ y - y1 = m1(x - x1) \\ y - 2 = 3(x - ( - 4)) \\ y = 3x + 12 + 2 \\ y = 3x + 14 \\ y - 3x - 14 = 0[/tex]