hasil dari 6 akar 3 + 5 akar 12 - akar 27 dan caranya no 7

[tex]6 \sqrt{3} + 5 \sqrt{12} - \sqrt{27} = \\ \: 6 \sqrt{3} \: + 5 \times 2 \sqrt{3} - 2 \times 3 \sqrt{3} \\ = 6 \sqrt{3} + 10 \sqrt{3} - 6 \sqrt{3} \\ = (6 + 10 - 6) \sqrt{3} \\ = 10 \sqrt{3} [/tex]