tentukan nilai lim → 2 x-2/3-√x²+5 = .... tentukan nilai lim → 1 1-x/2-√x+3 = ..... tolongin yaaa

Pertanyaan pertama:
lim →2 (x-2)/(3-√x²+5)
=lim →2
=(x-2)/(3-√x²+5) x (3+√x²+5)/(3+√x²+5)
=(x-2) (3+√x²+5) / 9-(x²+5)
=(x-2) (3+√x²+5) / 9-x²-5
=(2-2) (3+√2²+5) / 9-2²-5
=(0) (3+4+5) /9-4-5
=(0) (12)/0
=0/0
=0
Pertanyaan kedua:
lim (1 - x)(2 + √x+3)/(4 - (x + 3))
x->1
= lim (1 - x)(2 + √x+3)/(1 - x)
x->1
= lim (2 + √x+3)
x->1
= 2 + √4
= 4
Semoga membantu^^