larutan HCl 0,3 M dititrasi dengan larutan NaOH titik akhir titrasi tercapai bila 10 mL larutan HCL memerlukan 75 mL larutan NaOH Tentukan molaritas NaOH

HCl
M1 = 0,3 M
V1 = 75 mL

NaOH
M2 = ?
V2 = 10 mL

M1 × V1 = M2 × V2
0,3 × 75 = M2 × 10
22,5 = M2 × 10
M2 = 22,5/10
M2 = 2,25

Molaritas NaOH = 2,25 M

semoga membantu ^^

hcl. +. naoh----->nacl+h2o
10×0.3. = 75×M

3=75M
M=3/75=1/25=0.04