Diketahui h(x) = x³ + 5x² - x - 4. Nilai a yang memenuhi h(a) =46. Pake cara ya.

h'(x) =
[tex]3 {x}^{2} + 10x - 1[/tex]
h"(x)
[tex] = 6x + 10[/tex]
misal x =a
h"(a) =
[tex]6x + 10[/tex]
[tex]46 = 6a + 10 \\ 46 - 10 = 6a \\ 56 = 6a \\ a = 56 \div 6 \\ a = 9.33[/tex]