Fungsi f:R—>R ditentukan oleh g(x)=x^2-9 Dan g:R—>R memenuhi (gof)(X)=4x^2-12 maka f(x) adalah.... Tolong bantu jawab dong:(

mari kita selesaikan....;)
[tex]g(x) = {x}^{2} - 9 \\ (gof)(x) = 4 {x}^{2} - 12 \\ g(f(x)) = 4 {x}^{2} - 12 \\ {(f(x))}^{2} - 9 = 4 {x}^{2} - 12 \\ {(f(x))}^{2} = 4 {x}^{2} - 3 \\ f(x) = \sqrt{4 {x}^{2} - 3} [/tex]