jika 3log 5=q dan 2log 3=p maka nilai dari 36log 125

Logaritma


36log 125
= (6^2)log (5^3)
= 3/2 (6log 5)
= 3/2 (1/5log 6)
= 3/2 (1 / [5log 3+ 5log2]

2log 3 × 3log 5 = pq
2log 5 = pq
5log 2 = 1/pq

Maka
36log 125
= 3/2 ( 1/[(1/q) + 1/pq] )
= 3/2 ( pq / p+1)