Misalkan bentuk 3√24+2√3(√32-2√10) dapat disederhanakan menjadi?

[tex]3 \sqrt{24} + 2 \sqrt{3} ( \sqrt{32} - 2 \sqrt{10)} \\ = 3 \sqrt{24} + 2 \sqrt{96} - 4 \sqrt{30} \\ = 3.2 \sqrt{6} + 2.4 \sqrt{6} - 4 \sqrt{30} \\ = 6 \sqrt{6} + 8 \sqrt{6} - 4 \sqrt{30}[/tex]
[tex] = 14 \sqrt{6} - 4 \sqrt{30} [/tex]