jika fungsi g(x)=3x-2dan g° f(x) =6x + 10 tentukan f pangkat -1 (x)!

g o f(x) =6x + 10
g(f(x)) =6x + 10
3. f(x) - 2 = 6x + 10

3. f(x) = 6x + 12
f(x) = (6x + 12)/3
f(x) = 2x + 4

a= 2x+4
a-4 = 2x
x= (a-4)/2
f^(-1) (a) = (a-4)/2

ubah jadi x

f^(-1) (x) = (x-4)/2


semoga mmbantu