jika fungsi g(x)=3x-2dan g° f(x) =6x + 10 tentukan f pangkat -1 (x)!

Diketahui :
g(x) = 3x - 2
(g○f)(x) = 6x +10
Ditanyai :
f^-1(x) =...?
Jawab :
(g○f)(x) =(g(f(x)))
6x + 10 = 3(f(x))
f(x) = (6x + 10)/3
f^-1(x) = (-3x + 10)/-6
= (3x - 10)/6