8 log (x²+x)=8log12 tentukan nilai x
Matematika
gilangbro90p5x0pm
Pertanyaan
8 log (x²+x)=8log12 tentukan nilai x
1 Jawaban
-
1. Jawaban eripane05
Logaritma
8log (x^2 + x) = 8log 12
x^2 + x = 12
x^2 + x - 12 = 0
(x +4)(x-3) = 0
Hp = { -4 , 3 }