Nilai lim x=4 3-√x²-7/ x²-2x-8 tolong bantu Jawab kak:)

Limit

lim. (3- (x^2 -7)^1/2 / x^2 - 2x -8 )
x->4

Aturan L'Hospital
lim (-1/2 (2x) (x^2 -7)^-1/2 / 2x - 2)
x->4

= lim ( -x / (2x-2)(√x^2-7)
x->4

= -4 / (8-2) (√16-7)
= -4/ 6 (3)
= -2/9

[tex] \lim_{n \to \44} \frac{3- \sqrt{ x^{2} -7} }{ x^{2} -2x-8} [/tex]

diturunkan

[tex] \lim_{n \to \44} - \frac{2x}{2. \sqrt{ x^{2} -7}.(2x-2) } [/tex]
[tex]- \frac{8}{2. \sqrt{16-7}.6 } [/tex]
[tex]- \frac{2}{9} [/tex]