Matematika

Pertanyaan

nilai dari cos 68+cos 52: sin 52+sin 68

1 Jawaban

  • (cos68+cos52):(sin68+sin52)
    = (2cos(68+52)/2.cos(68-52)/2):(2sin(68+52)/2.cos(68-52)/2)
    =2cos60.cos8:2sin60.cos8
    =cos60:sin60
    =[tex] \frac{ \frac{ 1} {2} }{\frac{ \sqrt{3} }{2} } [/tex]
    =[tex] \frac{ \sqrt{3}}{3} [/tex]

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