nilai dari cos 68+cos 52: sin 52+sin 68
Matematika
naiya2602
Pertanyaan
nilai dari cos 68+cos 52: sin 52+sin 68
1 Jawaban
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1. Jawaban drshaun
(cos68+cos52):(sin68+sin52)
= (2cos(68+52)/2.cos(68-52)/2):(2sin(68+52)/2.cos(68-52)/2)
=2cos60.cos8:2sin60.cos8
=cos60:sin60
=[tex] \frac{ \frac{ 1} {2} }{\frac{ \sqrt{3} }{2} } [/tex]
=[tex] \frac{ \sqrt{3}}{3} [/tex]