tolong jawab pertanyaan ny iya

R1 = 4 + 4 = 8 Ω
R2 = 8 Ω
R3 = 4 + 2 + 2 = 8 Ω
R4 = 1 Ω
V = 10 volt
I?

penyelesaian:
Cari dulu hambatan pengganti:
1/Rp = 1/R1 + 1/R2 + 1/R3

1/Rp = 1/8 + 1/8 +1/8

1/Rp = 3/8

Rp = 8/3 = 2,66 Ω

R = Rp + R4 = 2,66 + 1 = 3,66 Ω

maka kuat arusnya:
I = V / R

I = 10 / 3,66

I = 2,73 Ampere