nilai dari [tex] {}^{2}log \frac{1}{32} + {}^{3}log27 = [/tex]

[tex] = - log_{2}(32) + log_{3}(27) [/tex]
[tex] = - log_{2}( {2}^{5} ) + log_{3}( {3}^{3} ) [/tex]
[tex] = ( - 5 \times 1) + (3 \times 1)[/tex]
[tex] = ( - 5) + 3[/tex]
[tex] = ( - 2)[/tex]