Pertanyaan saya berupa lampiran ., mohon dijelaskan sejelas2x

MAPEL = MATEMATIKA
KELAS = 9
BAB = AKAR & PANGKAT


[tex] \frac{2 \sqrt{6} }{ \sqrt{2} + \sqrt{5} } = \frac{2 \sqrt{6} }{ \sqrt{2} + \sqrt{5} } \times \frac{ \sqrt{2} - \sqrt{5} }{ \sqrt{2} - \sqrt{5} } \\ = \frac{2 \sqrt{6} ( \sqrt{2} - \sqrt{5} )}{2 - 5} \\ = \frac{2 \sqrt{12} - 2 \sqrt{30} }{ - 3} \\ = - \frac{2}{3} \sqrt{12} + \frac{2}{ 3} \sqrt{30} \\ = \frac{2}{3} \sqrt{30} - \frac{2}{3} \sqrt{12} [/tex]
jawaban B.
semoga membantu

[tex] \frac{2 \sqrt{6} }{ \sqrt{2} + \sqrt{5} } \\ = \frac{2 \sqrt{6} }{ \sqrt{2} + \sqrt{5} } \times \frac{ \sqrt{2} - \sqrt{5} }{ \sqrt{2} - \sqrt{5} } \\ = \frac{2 \sqrt{6} ( \sqrt{2} - \sqrt{5}) }{2 - 5} \\ = \frac{2 \sqrt{12} - 2 \sqrt{30} }{ - 3} \\ = \frac{2}{3} \sqrt{30} - \frac{2}{3} \sqrt{12} [/tex]
Semoga bermanfaat.....
-Prisco