f(x)= x³+4x²-6x+2 maka f'(2)=

f'(x) = 3x² + 8x-6
f'(2) = 3.2² + 8.2 - 6
f'(2) = 12+16-6
f'(2) = 22

Mapel : Matematika
Materi : Fungsi Turunan

f(x) = x³ + 4x² - 6x + 2

f'(x) = 3x² + 2(4)x - 6
f'(x) = 3x² + 8x - 6

Nilai f'(2)
= 3(2)² + 8(2) - 6
= 3(4) + 16 - 6
= 12 + 10
= 22