tolong bantu jawab dong..please penting banget soal ini hanya 2 soal kok

[tex] pq= \sqrt{ {qr}^{2} - {pr}^{2} } \\ = \sqrt{ {20}^{2} - {16}^{2} } \\ = \sqrt{400 - 266} \\ = \sqrt{144} \\ = 12 \\ po = \frac{1}{2} \times pq = \frac{1}{2} \times 12 = 6[/tex]

p-s=
√(169-144)=√25=5
s-q=√(400-144)=√256=16
untuk p-q=5+16=21