Tentukan nilai dari lim x→2 x3-4x x-2

[tex] \frac{ {x}^{3} - 4x }{x - 2} \\ = \frac{(x - 2)( {x}^{2} + 2x) }{x - 2} \\ = {x}^{2} + 2x \\ \\ = {2}^{2} + 2(2) = 4 + 4 = 8[/tex]

#semoga membantu :))