2log256 + 2log(1/16) - 2log64

Kelas 10 Matematika
Bab Logaritma

²log 256 + ²log (1/16) - ²log 64
= ²log 2⁸ + ²log 2⁻⁴ - ²log 2⁶
= 8 - 4 - 6
= -2

2log 256/16.64
=2log 1/4 = 2log (2)^-2
=-2 . 2log2
=-2